debug exposes a function; simply pass this function the name of your module, and it will return a decorated version of console.error for you to pass debug statements ...
(function() { slideshow_ad_loaded = true; adslots[slotName] = ...
JavaScript is a great language. It has a simple syntax, large ecosystem and, what is most important, a great community. At the same time, we all know that JavaScript is quite a funny language with ...
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